Question
You have a Wheatstone bridge circuit with three known resistors: R1 = 100Ω, R2 = 200Ω, and R3 = 300Ω. The bridge is balanced when an unknown resistor Rx is connected in the fourth arm
You have a Wheatstone bridge circuit with three known resistors: R1 = 100Ω, R2 = 200Ω, and R3 = 300Ω. The bridge is balanced when an unknown resistor Rx is connected in the fourth arm. If the ratio of R1 to Rx is 2:1, calculate the value of Rx.
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Koala Tutor
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To find the value of Rx, we need to use the balance condition of the Wheatstone bridge:
R1/Rx = R2/R3
Given that R1/Rx = 2/1, we can substitute this into the balance equation:
2/1 = 200Ω/300Ω
Cross-multiplying, we get:
2 * 300Ω = 1 * 200Ω
600Ω = 200Ω
Now, we can divide both sides of the equation by 200Ω to isolate Rx:
600Ω / 200Ω = Rx
Rx = 3 * 200Ω / 200Ω
Rx = 3
Therefore, the value of Rx is 3Ω.
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