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A 130-kg cart is accelerated horizontally by a 250-N force pulling at an angle of 20° above horizontal. Neglecting
A 130-kg cart is accelerated horizontally by a 250-N force pulling at an angle of 20° above horizontal. Neglecting rolling resistance, determine the acceleration of the cart.
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Koala Tutor
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The horizontal component of the force is given by Fcosθ = 250cos(20°) = 235.7 N.
The acceleration of the cart is given by Newton's second law, F = ma.
Rearranging for a gives a = F/m = 235.7 N / 130 kg = 1.81 m/s².
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