Question
Jan Villaroel
Topic: Physics Posted 1 year ago
A car accelerates from rest at a rate of 3 m/s² for 10 seconds, then maintains a constant speed of 30 m/s for another 20 seconds. Calculate the total distance traveled during this time.

A car accelerates from rest at a rate of 3 m/s² for 10 seconds, then maintains a constant speed of 30 m/s for another 20 seconds. Calculate the total distance traveled during this time.


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Koala Tutor
Oct 3, 2023
Koala Ai Support

To calculate the total distance traveled, we need to find the distances covered during the acceleration phase and the constant speed phase separately, and then add them together.

During the acceleration phase, we can use the equation:
distance = (initial velocity * time) + (0.5 * acceleration * time^2)

Given:
initial velocity = 0 m/s (starting from rest)
acceleration = 3 m/s²
time = 10 seconds

distance = (0 * 10) + (0.5 * 3 * 10^2)
distance = 0 + 0.5 * 3 * 100
distance = 0 + 0.5 * 300
distance = 0 + 150
distance = 150 meters

During the constant speed phase, the car maintains a speed of 30 m/s for 20 seconds. To find the distance covered, we can use the formula:
distance = speed * time

Given:
speed = 30 m/s
time = 20 seconds

distance = 30 * 20
distance = 600 meters

Therefore, the total distance traveled during this time period is 150 meters + 600 meters = 750 meters.

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