When 22.0 g of calcium metal is reacted with water, 5.00 g of calcium hydroxide is produced. Using the following balanced equation, calculate the percent yield for the reaction.
Ca + 2 H2O → Ca(OH)2 + H2
Guide On Rating System
Vote
To calculate the percent yield for the reaction, we first need to determine the theoretical yield of calcium hydroxide based on the amount of calcium metal used.
1. Calculate the molar mass of Ca(OH)2:
Ca: 1 atom x 40.08 g/mol = 40.08 g/mol
O: 2 atoms x 16.00 g/mol = 32.00 g/mol
H: 2 atoms x 1.01 g/mol = 2.02 g/mol
Total molar mass = 40.08 + 32.00 + 2.02 = 74.10 g/mol
2. Calculate the number of moles of Ca(OH)2 produced:
5.00 g Ca(OH)2 x (1 mol / 74.10 g) = 0.0674 mol Ca(OH)2
3. Use the mole ratio from the balanced equation to calculate the number of moles of Ca that reacted:
1 mol Ca reacts with 1 mol Ca(OH)2
0.0674 mol Ca(OH)2 x (1 mol Ca / 1 mol Ca(OH)2) = 0.0674 mol Ca
4. Calculate the theoretical yield of Ca(OH)2 based on the number of moles of Ca:
The molar mass of Ca is 40.08 g/mol
0.0674 mol Ca x 40.08 g/mol = 2.70 g Ca
5. Now we can calculate the percent yield:
Percent Yield = (Actual Yield / Theoretical Yield) x 100%
Percent Yield = (5.00 g / 2.70 g) x 100% = 185.19%
Therefore, the percent yield for the reaction is 185.19%
Got a question with my answer?
Cheapmath.com is completely free!
Asking question is free.
Getting answers is free.
+99