a) No, you could not separate the components of a mixture of Mg(OH)2 and Zn(OH)2 by using 3 M HCl. This is because both Mg(OH)2 and Zn(OH)2 are not soluble in cold water, hot water, or 3 M HCl.

b) No, a mixture of benzoic acid and Mg(OH)2 cannot be separated by using 3 M NaOH. This is because benzoic acid is soluble in hot water and 3 M NaOH, but Mg(OH)2 is not soluble in either. However, the mixture can be separated by using 3 M HCl. Benzoic acid will react with 3 M HCl to form a salt that is soluble in water, while Mg(OH)2 will remain insoluble.

c) To separate the components of a mixture of benzoic acid and Zn(OH)2 and recover both substances, the following procedural steps can be followed:

Step 1: Dissolve the mixture in hot water. This will dissolve the benzoic acid, as it is soluble in hot water, but leave the Zn(OH)2 undissolved.

Step 2: Filter the mixture to separate the insoluble Zn(OH)2 from the solution containing benzoic acid.

Step 3: Evaporate the water from the filtered solution to recover the benzoic acid.

Step 4: Add 3 M NaOH to the Zn(OH)2 residue from the filtration. Zn(OH)2 is insoluble in 3 M NaOH, so it will remain as a solid while any impurities dissolve.

Step 5: Filter the mixture again to separate the Zn(OH)2 from the 3 M NaOH solution.

Step 6: Wash the Zn(OH)2 with cold water to remove any remaining impurities.

Step 7: Dry the Zn(OH)2 to recover the solid substance.

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