Balance the following chemical equation:
Na2CO3(aq) + CaCl2(aq) → CaCO3(s) + NaCl(aq)
Use the balanced chemical equation from the last question to solve this situation: You combine 0.5 moles of Na2CO3 with enough CaCl2 that your compound reacts completely. How many moles of NaCl would you expect this reaction to produce? Show all work below.
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From the balanced equation, we can see that the stoichiometric ratio between Na2CO3 and NaCl is 1:2. Therefore, if 1 mole of Na2CO3 reacts, it will produce 2 moles of NaCl.
Since we are given that we have 0.5 moles of Na2CO3, we can calculate the moles of NaCl produced as follows:
0.5 moles Na2CO3 × (2 moles NaCl / 1 mole Na2CO3) = 1 mole NaCl
Therefore, we would expect this reaction to produce 1 mole of NaCl.
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