Question
Jan Villaroel
Topic: Algebra Posted 1 year ago
The sum of the ages of a woman and her daughter is 46. Six years ago, the woman was five times as old as her daughter. How old are they now?

The sum of the ages of a woman and her daughter is 46. Six years ago, the woman was five times as old as her daughter. How old are they now?


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Koala Tutor
Nov 4, 2023
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Let's say the daughter's age is x now.
Six years ago, the daughter was x-6 years old.
Six years ago, the woman was 5(x-6) = 5x-30 years old.
The sum of their ages six years ago is 46-12 = 34 years
The sum of their ages now is 34+12 = <<34+12=46>>46 years
The daughter's age now is x = 46 - 30 = <<46-30=16>>16 years.
The woman's age now is 46-16 = <<46-16=30>>30 years. Answer: \boxed{16, 30}.

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