Question
The standard enthalpy change for the following reaction is -220 kJ at 298 K. Cu(s) + Cl2(g) CuCl2(s) ΔH° = -220 kJ
The standard enthalpy change for the following reaction is -220 kJ at 298 K.
Cu(s) + Cl2(g) CuCl2(s) ΔH° = -220 kJ
What is the standard enthalpy change for the reaction at 298 K?
CuCl2(s) -> Cu(s) + Cl2(g)
________ kJ
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Koala Tutor
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To find the standard enthalpy change for the reaction CuCl2(s) -> Cu(s) + Cl2(g), we can use the fact that the enthalpy change is equal in magnitude but opposite in sign.
Therefore, the standard enthalpy change for the reaction CuCl2(s) -> Cu(s) + Cl2(g) is +220 kJ.
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