Question
Jan Villaroel
Topic: Algebra Posted 1 year ago
The present age of Jacob’s father is three times that of Jacob. After 5 years, sum of their ages would be 70 years. Find their present ages.

The present age of Jacob’s father is three times that of Jacob. After 5 years, sum of their ages would be 70 years. Find their present ages.


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Koala Tutor
Nov 21, 2023
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Let's say Jacob's present age is J and his father's present age is F.

According to the problem, the present age of Jacob’s father is three times that of Jacob, so we can write the equation:

F = 3J

After 5 years, Jacob's age will be J + 5 and his father's age will be F + 5. We are given that the sum of their ages after 5 years would be 70 years, so we can write the equation:

(J + 5) + (F + 5) = 70

Substituting F = 3J from the first equation into the second equation:

(J + 5) + (3J + 5) = 70

Combining like terms:

4J + 10 = 70

Subtracting 10 from both sides:

4J = 60

Dividing both sides by 4:

J = 15

Substituting J = 15 into F = 3J:

F = 3(15) = 45

Therefore, Jacob's present age is 15 and his father's present age is 45.

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