The concentration of carbon monoxide in an urban apartment is 48 μg/m3. What is the mass, in grams, of carbon monoxide present in a room measuring 14.5 ft X 14.8 ft X 20.5 ft?
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To find the mass of carbon monoxide present in the room, we need to convert the volume of the room from cubic feet to cubic meters.
Given:
Length = 14.5 ft
Width = 14.8 ft
Height = 20.5 ft
To convert these measurements to meters, we need to multiply each measurement by 0.3048 (since 1 ft is equal to 0.3048 m).
Length = 14.5 ft * 0.3048 = 4.419 m
Width = 14.8 ft * 0.3048 = 4.511 m
Height = 20.5 ft * 0.3048 = 6.248 m
Now we can calculate the volume of the room in cubic meters:
Volume = Length * Width * Height
Volume = 4.419 m * 4.511 m * 6.248 m
Volume ≈ 125.083 m^3
Now we can calculate the mass of carbon monoxide present in the room using the concentration given:
Mass = Concentration * Volume
Mass = 48 μg/m^3 * 125.083 m^3
To convert μg (micrograms) to grams, we divide by 1,000,000:
Mass ≈ (48/1,000,000) g/m^3 * 125.083 m^3
Mass ≈ 0.002402 g
Therefore, the mass of carbon monoxide present in the room is approximately 0.002402 grams.
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