Suppose the bit patterns in 8-bit two’s complement representation are replaced by hexadecimal
digits. Perform the indicated operations.
a. A1 + 2A
b. A1 + 81
c. A1 – 9A
d. FF – AA
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a. To add A1 and 2A, we first need to convert A1 and 2A to their decimal equivalents:
A1 = -95
2A = 42
Adding -95 and 42 gives us -53. Converting -53 back to hexadecimal, we get CD.
Therefore, A1 + 2A = CD.
b. To add A1 and 81, we convert A1 and 81 to their decimal equivalents:
A1 = -95
81 = -127
Adding -95 and -127 gives us -222. Converting -222 back to hexadecimal, we get DE.
Therefore, A1 + 81 = DE.
c. To subtract 9A from A1, we convert A1 and 9A to their decimal equivalents:
A1 = -95
9A = -102
Subtracting -102 from -95 gives us 7. Converting 7 back to hexadecimal, we get 07.
Therefore, A1 - 9A = 07.
d. To subtract AA from FF, we convert AA and FF to their decimal equivalents:
AA = -86
FF = -1
Subtracting -86 from -1 gives us 85. Converting 85 back to hexadecimal, we get 55.
Therefore, FF - AA = 55.
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