Suppose Host A wants to send a large file to Host B. The path from Host A to Host B has three links of rate R1=100Mbps, R2=500Mbps, and R3=200Mbps.
(a) Assume no other traffic in the network, what is the throughput for the file transfer?
(b) Suppose the file is 500MB (Assume 1MB= 106 bytes). Dividing the file size by the throughput, roughly how long will it take to transfer the file to Host B?
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(a) The throughput for the file transfer can be determined by the bottleneck link, which in this case is the link with the lowest rate, R3=200Mbps. So, the throughput would be 200Mbps.
(b) The file size is 500MB, which is equal to 500 * 10^6 bytes. Dividing this by the throughput of 200Mbps (200 * 10^6 bits per second) gives us the time it would take to transfer the file:
Time = (500 * 10^6 bytes) / (200 * 10^6 bits per second) = 2.5 seconds.
So, it would take roughly 2.5 seconds to transfer the file to Host B.
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