Refer to the following equation: 4NH3+7O2->4NO2+6H2O
How many molecules of water are produced if 1.76 mol of NO2 is given off?
a. 2.12 × 1024
b. 1.06 × 1024
c. 31.7
d. 1.59 × 1024
e. none of these
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To find the number of molecules of water produced, we can use the coefficient ratio from the balanced equation.
From the equation, we see that 4 moles of NH3 produces 6 moles of H2O.
Therefore, 1 mol of NH3 produces (6/4) = 1.5 moles of H2O.
Since 4 moles of NH3 produces 7 moles of O2, we can use this ratio to find the moles of O2 produced from 1.76 mol of NO2.
Using the ratio 4 moles of NH3 to 7 moles of O2, we can set up the following proportion:
(1.76 mol NO2) / (4 mol NH3) = (x mol O2) / (7 mol O2)
Cross-multiplying gives us:
(1.76 mol NO2)(7 mol O2) = (4 mol NH3)(x mol O2)
12.32 mol O2 = 4x mol O2
x = (12.32 mol O2) / 4 = 3.08 mol O2
Since 4 moles of NH3 produces 6 moles of H2O, we can use this ratio to find the moles of H2O produced from 3.08 mol of O2.
Using the ratio 4 moles of NH3 to 6 moles of H2O, we can set up the following proportion:
(3.08 mol O2) / (4 mol NH3) = (x mol H2O) / (6 mol H2O)
Cross-multiplying gives us:
(3.08 mol O2)(6 mol H2O) = (4 mol NH3)(x mol H2O)
18.48 mol H2O = 4x mol H2O
x = (18.48 mol H2O) / 4 = 4.62 mol H2O
Therefore, 4.62 mol of H2O is produced.
To find the number of molecules, we can use Avogadro's number, which is approximately 6.022 × 10^23 molecules/mol.
Number of molecules = (4.62 mol H2O) * (6.022 × 10^23 molecules/mol) = 2.78 × 10^24 molecules
Therefore, the correct answer is e. none of these.