Reacting 3.00 mol nitrogen gas with 3.59 mol hydrogen gas will produce how many moles of ammonia according to the following balanced chemical equation?

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RONALD OLUOCH

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Topic: Chemistry Posted 1 year ago

Reacting 3.00 mol nitrogen gas with 3.59 mol hydrogen gas will produce how many moles of ammonia according to the following balanced chemical equation?

Reacting 3.00 mol nitrogen gas with 3.59 mol hydrogen gas will produce how many moles of ammonia according to the following balanced chemical equation?

N2 + 3H2 -> 2NH3

a. 3.59 mol NH3
b. 5.39 mol NH3
c. 2.39 mol NH3
d. 7.18 mol NH3
e. 6.00 mol NH3

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Oct 1, 2023

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According to the balanced chemical equation, 1 mol of nitrogen gas reacts with 3 mol of hydrogen gas to produce 2 mol of ammonia.

Since the reaction involves 3.00 mol of nitrogen gas and 3.59 mol of hydrogen gas, we can calculate the number of moles of ammonia produced using the ratio from the balanced chemical equation:

3.00 mol N2 * (2 mol NH3 / 1 mol N2) = 6.00 mol NH3

Therefore, the reaction will produce 6.00 mol of ammonia.

The correct answer is e. 6.00 mol NH3.

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