Propane (C3H8) is burned in excess oxygen (O2) to produce carbon dioxide (CO2) and water (H2O). Calculate the volume of CO2 produced at STP when 2 moles of propane react
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To calculate the volume of CO2 produced at STP when 2 moles of propane react, we need to use the balanced chemical equation for the combustion of propane:
C3H8 + 5O2 -> 3CO2 + 4H2O
From the balanced equation, we can see that 1 mole of propane produces 3 moles of carbon dioxide.
So, 2 moles of propane will produce (2 moles propane) x (3 moles CO2 / 1 mole propane) = 6 moles of carbon dioxide.
Now, we need to calculate the volume of carbon dioxide at STP. 1 mole of any gas at STP occupies 22.4 Liters.
Therefore, 6 moles of carbon dioxide will occupy (6 moles CO2) x (22.4 Liters / 1 mole CO2) = 134.4 Liters of carbon dioxide at STP.
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