consider a rectangle, for which perimeter=2l+2w. perimeter = 2 l + 2 w . If the length of a rectangle is 5 m less than twice the width, and the perimeter is 44 m long, find its length and width.
Guide On Rating System
Vote
Let's solve this step by step:
Let's assume the width of the rectangle is "w" meters.
So, the length of the rectangle would be 2w - 5 meters (as it is stated that "the length of a rectangle is 5 m less than twice the width").
We know that the perimeter is given by the formula 2l + 2w.
Substituting the values we have:
2(2w - 5) + 2w = 44
Expanding the equation:
4w - 10 + 2w = 44
Combining like terms:
6w - 10 = 44
Adding 10 to both sides of the equation:
6w = 54
Now, we can solve for "w" by dividing both sides of the equation by 6:
w = 9
Therefore, the width of the rectangle is 9 meters.
To find the length, we substitute the value of the width into the expression 2w - 5:
length = 2(9) - 5
length = 18 - 5
length = 13
So, the length of the rectangle is 13 meters.
Therefore, the length of the rectangle is 13 meters and the width is 9 meters.
Got a question with my answer?
Cheapmath.com is completely free!
Asking question is free.
Getting answers is free.
+99