In the laboratory a student finds that it takes 2.21×103 Joules to increase the temperature of 10.8 grams of gaseous hydrogen from 20.5 to 36.0 degrees Celsius.
The specific heat of hydrogen calculated from her data is___J/g°C.
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To calculate the specific heat (c) of hydrogen, we can use the formula:
Q = mcΔT
where Q is the heat energy absorbed by the substance, m is the mass of the substance, c is the specific heat, and ΔT is the change in temperature.
In this case, we are given:
Q = 2.21×10^3 J
m = 10.8 g
ΔT = (36.0 - 20.5) °C = 15.5 °C
Plugging in these values into the formula, we have:
2.21×10^3 J = (10.8 g) * c * 15.5 °C
Solving for c, we divide both sides of the equation by 10.8 grams * 15.5 °C:
c = 2.21×10^3 J / (10.8 g * 15.5 °C)
Calculating this expression gives us:
c ≈ 11.54 J/g°C
Therefore, the specific heat of hydrogen calculated from the data is approximately 11.54 J/g°C.
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