In the laboratory a student finds that it takes 2.21×103 Joules to increase the temperature of 10.8 grams of gaseous hydrogen from 20.5 to 36.0 degrees Celsiu

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Topic: Chemistry Posted 1 year ago

In the laboratory a student finds that it takes 2.21×103 Joules to increase the temperature of 10.8 grams of gaseous hydrogen from 20.5 to 36.0 degrees Celsiu

In the laboratory a student finds that it takes 2.21×103 Joules to increase the temperature of 10.8 grams of gaseous hydrogen from 20.5 to 36.0 degrees Celsius.

The specific heat of hydrogen calculated from her data is___J/g°C.

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Koala Tutor

Oct 1, 2023

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To calculate the specific heat of hydrogen, we can use the formula:

q = mcΔT

Where:
q = heat energy (Joules)
m = mass (grams)
c = specific heat (J/g°C)
ΔT = change in temperature (in Celsius)

Given:
q = 2.21×10^3 J
m = 10.8 g
ΔT = 36.0°C - 20.5°C = 15.5°C

Rearranging the formula, we have:

c = q / (m * ΔT)

Plugging in the given values, we get:

c = 2.21×10^3 J / (10.8 g * 15.5°C)

Calculating the value, we have:

c ≈ 12.90 J/g°C

Therefore, the specific heat of hydrogen calculated from her data is approximately 12.90 J/g°C.

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