Question
If three times the first of three consecutive odd integers is added to twice the second, the result is 47. Find the integers.
If three times the first of three consecutive odd integers is added to twice the second, the result is 47. Find the integers.
Answers
What are best answers and total votes?
Guide On Rating System
✅
Best Answers -
Rating provided by student who posted the question
Total Votes -
Sum of votes provided by verified experts based on their
assessment of the answer. For example, total votes of 2
means 2 verified experts have approved the answer.
In most cases Best Answers have also the most Total Votes but when
this is not the case, kindly review the feedbacks from verified experts
and decide which answer to take.
No Votes
Vote
SignIn to Vote
Vote
Vote
Loading...
Koala Tutor
Koala Ai Support
Got a question with my answer?
Let's assume that the first odd integer is $x$. Therefore, the second odd integer would be $x+2$, and the third odd integer would be $x+4$.
According to the given condition, three times the first odd integer is equal to twice the second odd integer plus $47$: $$3x = 2(x+2) + 47$$
Simplifying the equation, we have: $$3x = 2x + 4 + 47$$ $$3x = 2x + 51$$
Subtracting $2x$ from both sides, we get: $$x = 51$$
Therefore, the first odd integer is $51$, the second odd integer is $51+2=53$, and the third odd integer is $51+4=55$.
Got a question with my answer?
Message Me
Cheapmath.com is completely free!
Asking question is free.
Getting answers is free.
+99
Asking question is free.
Getting answers is free.
+99