How much work (in J) is involved in a chemical reaction if the volume decreases from 4.7 to 1.03 L against a constant pressure of 0.875 atm?

Question

Topic: Chemistry Posted 10 months ago

Answers

What are best answers and total votes?

No Votes

Vote

SignIn to Vote

Feb 20, 2024

Koala Ai Support

To calculate the work involved in a chemical reaction where the volume decreases against a constant pressure, we can use the formula:

W = -PΔV

Where:
W = work
P = pressure (0.875 atm)
ΔV = change in volume (final volume - initial volume)

First, we need to calculate the change in volume:

ΔV = 1.03 L - 4.7 L
ΔV = -3.67 L

Now we can calculate the work:

W = -0.875 atm * (-3.67 L)
W = 3.21125 atm*L

Since 1 atm*L = 101.3 J, we can convert the result to joules:

W = 3.21125 atm*L * 101.3 J
W = 325.239875 J

Therefore, the work involved in the chemical reaction is approximately 325.24 J.

Got a question with my answer?

Message Me

Community

✅ Completely FREE!

✅ Powered by GPT-4

Marketplace

✅ Get unlimited help from freelance Math experts.

Premium (Coming Soon)

✅ GPT-4 + Premium Access

Guide On Rating System