How many milliseconds (ms) does it take for a packet of length 1,000 bytes to be delivered from the sending host to the receiving host over a link of distance 2,000 km, propagation speed 2.5x108 m/s, and transmission rate 50Mbps (consider both transmission delay and propagation delay)?
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To calculate the total time for the packet to be delivered, we need to consider both the transmission delay and the propagation delay.
Transmission delay: This is the time required to transmit the packet over the link. It can be calculated using the formula:
Transmission delay = Packet length / Transmission rate
Packet length = 1,000 bytes = 1,000 * 8 bits = 8000 bits
Transmission rate = 50 Mbps = 50,000,000 bits per second
Transmission delay = 8000 bits / 50,000,000 bits per second
= 0.00016 seconds
Propagation delay: This is the time required for a signal to travel from the sending host to the receiving host over the link. It can be calculated using the formula:
Propagation delay = Distance / Propagation speed
Distance = 2,000 km = 2,000,000 meters
Propagation speed = 2.5 * 10^8 m/s
Propagation delay = 2,000,000 meters / (2.5 * 10^8 m/s)
= 0.008 seconds
Total delay = Transmission delay + Propagation delay
= 0.00016 seconds + 0.008 seconds
= 0.00816 seconds
To convert this to milliseconds (ms), we multiply by 1,000:
Total delay = 0.00816 seconds * 1,000 ms/second
= 8.16 ms
Therefore, it takes 8.16 milliseconds for a packet of length 1,000 bytes to be delivered from the sending host to the receiving host over a link of distance 2,000 km, propagation speed 2.5x10^8 m/s, and transmission rate 50 Mbps.
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