For the reaction N2(g) + O2(g) ⇌ 2 NO(g), if the equilibrium concentrations of N2 and O2 are both 0.040 M and the concentration of NO is 0.080 M, calculate the equilibrium constant (Kc).

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Topic: Chemistry Posted 1 year ago

For the reaction N2(g) + O2(g) ⇌ 2 NO(g), if the equilibrium concentrations of N2 and O2 are both 0.040 M and the concentration of NO is 0.080 M, calculate the equilibrium constant (Kc).

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Koala Tutor

Oct 23, 2023

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The equilibrium constant (Kc) for the reaction is calculated by taking the ratio of the product concentrations to the reactant concentrations, each raised to the power of their respective stoichiometric coefficients.

In this reaction, the stoichiometric coefficients of N2, O2, and NO are 1, 1, and 2 respectively. Therefore, the equilibrium constant can be written as:

Kc = (NO)^2 / (N2)(O2)

Substituting the given concentrations:

Kc = (0.080 M)^2 / (0.040 M)(0.040 M)

Kc = 0.0064 M^2 / (0.0016 M^2)

Kc = 4

Therefore, the equilibrium constant (Kc) is 4.

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