Question
For the reaction N2(g) + 3 H2(g) ⇌ 2 NH3(g), if the equilibrium concentrations of NH3 and H2 are both 0.10 M, and the concentration of N2 is 0.05 M, calculate the equilibrium constant (Kc).
For the reaction N2(g) + 3 H2(g) ⇌ 2 NH3(g), if the equilibrium concentrations of NH3 and H2 are both 0.10 M, and the concentration of N2 is 0.05 M, calculate the equilibrium constant (Kc).
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Koala Tutor
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The equilibrium constant, Kc, is calculated using the formula:
Kc = [NH3]^2 / ([N2] x [H2]^3)
Plugging in the given equilibrium concentrations:
[NH3] = 0.10 M
[N2] = 0.05 M
[H2] = 0.10 M
Kc = (0.10)^2 / (0.05 x 0.10^3)
= 0.01 / (0.05 x 0.001)
= 0.01 / 0.00005
= 200
Therefore, the equilibrium constant (Kc) for the given reaction is 200.
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