To determine the number of grams of CaCl2 that can be obtained, we need to calculate the molar mass of CaCl2 and then use stoichiometry to convert the given mass of HCl to grams of CaCl2.

The molar mass of CaCl2 is calculated as follows:

Ca: atomic mass = 40.08 g/mol
Cl: atomic mass = 35.45 g/mol (x2 for 2 Cl atoms)
CaCl2: (40.08 g/mol) + (35.45 g/mol x 2) = 110.98 g/mol

Now we can set up the stoichiometry calculation using the balanced equation:

1 mol CaCO3 + 2 mol HCl -> 1 mol CaCl2 + 1 mol CO2 + 1 mol H2O

From the balanced equation, we can see that the ratio is 1:1 for CaCO3 to CaCl2. This means that for every 1 mol of CaCO3, 1 mol of CaCl2 is produced.

First, we need to convert the given mass of HCl to moles using its molar mass:

43.5 g HCl x (1 mol HCl / 36.46 g HCl) = 1.19 mol HCl

Since we have a 1:1 ratio of CaCO3 to CaCl2, the moles of CaCl2 that can be obtained is also 1.19 mol.

Finally, we convert moles of CaCl2 to grams:

1.19 mol CaCl2 x (110.98 g CaCl2 / 1 mol CaCl2) = 132.327 g CaCl2

Therefore, the answer is approximately 132 g CaCl2.

The correct answer is a. 132 g CaCl2.

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