Determine the stoichiometry of the reaction between sodium (Na) and chlorine (Cl2) to form sodium chloride (NaCl) in terms of the number of atoms involved.
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The stoichiometry of a chemical reaction refers to the relative quantities of reactants and products in the balanced chemical equation. In this case, the reaction between sodium and chlorine to form sodium chloride is represented by the equation:
2Na + Cl2 -> 2NaCl
From the balanced equation, we can see that for every 2 sodium atoms (2Na), we need 1 molecule of chlorine gas (Cl2). The reaction produces 2 molecules of sodium chloride (2NaCl).
Therefore, in terms of the number of atoms involved, the stoichiometry of the reaction is:
2Na + Cl2 -> 2NaCl
This means that 2 sodium atoms react with 1 chlorine molecule to form 2 sodium chloride molecules.