Determine the amount of oxygen gas (O2) dissolved in a 1,000 mL sample of river water, given that the water contains 4.5 mg/L of dissolved oxygen
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To determine the amount of oxygen gas dissolved in the river water, we need to convert the concentration of dissolved oxygen from mg/L to moles/L.
1. Convert 4.5 mg/L to grams/L:
4.5 mg/L = 4.5 × 10^(-3) g/L
2. Convert grams/L to moles/L:
The molar mass of oxygen (O2) is 32 g/mol.
So, 4.5 × 10^(-3) g/L ÷ 32 g/mol ≈ 0.00014 mol/L
Now, we can calculate the amount of oxygen gas dissolved in the 1,000 mL (or 1 L) sample of river water.
3. Multiply the concentration in moles/L by the volume in liters:
0.00014 mol/L × 1 L = 0.00014 mol
Therefore, there are approximately 0.00014 moles of oxygen gas (O2) dissolved in the 1,000 mL sample of river water.
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