5.On complete combustion of 5 liters (T,P) of a gaseous alkane, 15 liters (T.P) of carbon dioxide is produced. Write the molecular formula of the alkane...
6. Write the equation for the following reaction:
a. Preparation of alkene from 1-bromopentane with KOH solution in ethanol
b. Preparation of alkyl halide from 1-butanol with hydrogen bromide
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5. The general formula for the combustion of an alkane is CnH2n+2 + (3n+1)/2 O2 -> n CO2 + (n+1) H2O. From the problem, we know that 5 liters of alkane produces 15 liters of CO2. This means that the ratio of alkane to CO2 is 1:3. Therefore, n=3. So, the molecular formula of the alkane is C3H8, which is propane.
6.
a. The reaction for the preparation of alkene from 1-bromopentane with KOH solution in ethanol is:
C5H11Br + KOH -> C5H10 + KBr + H2O
This is an elimination reaction where KOH acts as a base to remove a hydrogen atom and a bromine atom, forming an alkene (pentene).
b. The reaction for the preparation of alkyl halide from 1-butanol with hydrogen bromide is:
C4H9OH + HBr -> C4H9Br + H2O
This is a substitution reaction where the hydroxyl group (OH) in the alcohol (butanol) is replaced by a bromine atom, forming an alkyl halide (1-bromobutane).
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