Question
Jan Villaroel
Topic: Physics Posted 1 year ago
Calculate the escape velocity required for an object to break free from the surface of a rotating space station, where the station's radius decreases from 200 meters to 100 meters.

Calculate the escape velocity required for an object to break free from the surface of a rotating space station, where the station's radius decreases from 200 meters to 100 meters.


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Koala Tutor
Oct 14, 2023
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To calculate the escape velocity required for an object to break free from the surface of a rotating space station, we can use the principle of conservation of angular momentum.

The angular momentum is given by the equation:

L = Iω

Where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

In the case of a rotating space station, the moment of inertia I can be calculated as:

I = (2/5) m r²

Where m is the mass of the object and r is the radius of the space station.

Since the space station is rotating, the angular velocity ω can be determined using the equation:

ω = v / r

Where v is the linear velocity of the object and r is the radius.

To break free from the surface of the rotating space station, the object's velocity must be equal to or greater than the escape velocity. The escape velocity can be defined as:

v_escape = √(2G M / r)

Where G is the gravitational constant, M is the mass of the space station, and r is the distance from the center of the space station to the object.

To calculate the escape velocity at the surface of a rotating space station with a radius that decreases from 200 meters to 100 meters, we need to consider the angular momentum and the escape velocity at each radius.

1. Calculate the angular momentum at r = 200 m:
L_1 = I_1 ω_1
= [(2/5) m (200 m)²] (v / 200 m)
= (8/5) m v

2. Calculate the escape velocity at r = 200 m:
v_escape_1 = √(2G M / r)
= √[(2G M) / (200 m)]

3. Calculate the angular momentum at r = 100 m:
L_2 = I_2 ω_2
= [(2/5) m (100 m)²] (v / 100 m)
= (2/5) m v

4. Calculate the escape velocity at r = 100 m:
v_escape_2 = √(2G M / r)
= √[(2G M) / (100 m)]

Now, we can compare the angular momentum and the escape velocity at each radius to determine the required escape velocity.

Since the angular momentum is conserved in this system, we have L_1 = L_2, and (8/5) m v = (2/5) m v.
This implies that v_1 = v_2.

Therefore, the escape velocity required for an object to break free from the surface of the rotating space station is the same at both radii, and it is given by:

v_escape = √[(2G M) / (200 m)] = √[(2G M) / (100 m)]

Please note that in this calculation, we assume a point mass for the space station and neglect any effects due to the station's rotation on the escape velocity. This is a simplified approach, and in reality, the escape velocity might be slightly different due to the rotation of the space station.

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