Calculate the buoyant force on a 2 kg solid iron cube submerged in water. Determine the apparent weight of the cube in the water.
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To calculate the buoyant force on the iron cube, we need to use Archimedes' principle, which states that the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
The density of water is approximately 1000 kg/m^3, and the density of iron is 7870 kg/m^3.
The volume of the cube can be calculated using its mass and the density of iron:
Volume = Mass / Density = 2 kg / 7870 kg/m^3 = 0.000254 m^3.
The buoyant force can be calculated using the volume of the cube and the density of water:
Buoyant Force = Density of Water * Volume * Acceleration due to Gravity
= 1000 kg/m^3 * 0.000254 m^3 * 9.8 m/s^2
= 2.49692 N.
Therefore, the buoyant force on the 2 kg iron cube submerged in water is approximately 2.49692 N.
To determine the apparent weight of the cube in the water, we need to subtract the buoyant force from the weight of the cube.
Weight = Mass * Acceleration due to Gravity = 2 kg * 9.8 m/s^2 = 19.6 N.
Apparent Weight = Weight - Buoyant Force = 19.6 N - 2.49692 N = 17.10308 N.
Therefore, the apparent weight of the 2 kg iron cube in water is approximately 17.10308 N.
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