Question
Jan Villaroel
Topic: Chemistry Posted 1 year ago
After the label fell of a bottle containing a clear liquid believed to be benzene, a chemist measured the density of the liquid to verify its identity

After the label fell of a bottle containing a clear liquid believed to be benzene, a chemist measured the density of the liquid to verify its identity. A 25.0 mL portion of the liquid had a mass of 21.97 g. A chemistry handbook list the density of benzene at 15 °C as 0.8787 g/mL. Is the calculated value in agreement with the literature value?


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Koala Tutor
Aug 26, 2023
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To solve this problem, we can calculate the density of the liquid using the given measurements and then compare it to the literature value for benzene.

Density is calculated by dividing the mass of a substance by its volume. In this case, the mass of the liquid is given as 21.97 g, and the volume is given as 25.0 mL.

Density = mass/volume = 21.97 g / 25.0 mL

To compare this calculated value to the literature value, we can divide it by the literature value and multiply by 100 to calculate the percentage difference.

Percentage difference = (calculated value / literature value) * 100

Let's plug in the values and calculate:

Percentage difference = (21.97 g / 25.0 mL) / 0.8787 g/mL * 100

= (0.8788) / 0.8787 * 100

= 100.0114

The calculated value of the density is 100.0114% of the literature value. Since this is very close to 100%, we can conclude that the calculated value is in agreement with the literature value.

Therefore, the calculated value is in agreement with the literature value for benzene.

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