Question
A sum of money is divided among A, B, and C in the ratio of 3:4:5. If B receives $600 more than A, what is the total amount they receive?
A sum of money is divided among A, B, and C in the ratio of 3:4:5. If B receives $600 more than A, what is the total amount they receive?
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Let the total sum of money be x.
The ratio of A, B, and C is 3:4:5, which means that the shares of A, B, and C are 3/12, 4/12, and 5/12 respectively.
Since B receives $600 more than A, the share of B is 4/12 + $600 = 1/3 + $600.
This is equal to 1/3 of the total sum of money, which is x/3.
Therefore, 1/3x = $600, or x = $600 * 3 = $<<600*3=1800>>1800.
The total amount they receive is 1800 * (3/12 + 4/12 + 5/12) = 1800 * (12/12) = $<<1800*12/12=1800>>1800. Answer: \boxed{1800}.
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