A school bus travels at 45 mph, and a car at 60 mph. If the car leaves 2 hours later, when will it catch up to the bus?
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To solve this problem, we need to find out the time it takes for the car to catch up to the bus.
Let's assume that when the car catches up to the bus, both the car and the bus have traveled the same distance.
Let's say the time it takes for the car to catch up to the bus is 't' hours.
In the time 't', the bus has already traveled for 't + 2' hours because it left 2 hours earlier.
Distance covered by the bus = Speed × Time
Distance covered by the car = Speed × Time
Since the distances are equal when the car catches up to the bus, we can set up the equation:
45(t + 2) = 60t
Expanding the equation, we get:
45t + 90 = 60t
Now, we can solve for 't':
15t = 90
t = 6
Therefore, it will take the car 6 hours to catch up to the bus.
To find out when this will happen, we add the 6 hours to the time the car leaves:
Time the car catches up to the bus = 2 hours (the time the car left) + 6 hours (the time it takes to catch up)
Time the car catches up to the bus = 8 hours
So, the car will catch up to the bus 8 hours after it left.
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