A sample of iron ore is titrated with a potassium dichromate (K2Cr2O7) solution. If it takes 30.0 mL of 0.025 M K2Cr2O7 to reach the endpoint, calculate the mass percent of iron in the ore sample.
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To calculate the mass percent of iron in the ore sample, we need to use stoichiometry and the volume and concentration of the potassium dichromate solution. Here's how we can solve it step by step:
1. Write the balanced equation for the reaction between potassium dichromate and iron:
6 Fe2+ (aq) + Cr2O7^2- (aq) + 14 H+ (aq) → 6 Fe3+ (aq) + 2 Cr3+ (aq) + 7 H2O (l)
2. Determine the moles of potassium dichromate used:
moles K2Cr2O7 = volume (L) × molarity (mol/L)
= 0.0300 L × 0.025 mol/L
= 0.00075 mol
3. Since the reaction between potassium dichromate and iron has a 1:6 stoichiometric ratio, the moles of iron in the sample can be calculated as:
moles Fe = 6 × moles K2Cr2O7
= 6 × 0.00075 mol
= 0.00450 mol
4. Determine the mass of iron in the sample:
mass Fe = moles Fe × molar mass Fe
= 0.00450 mol × 55.845 g/mol
= 0.251 g
5. Finally, calculate the mass percent of iron in the ore sample:
mass percent Fe = (mass Fe / mass of ore sample) × 100%
= (0.251 g / mass of ore sample) × 100%
Note: The mass of the ore sample is not provided in the question, so you need to use that information to calculate the mass percent of iron in the sample.