A reaction between zinc (Zn) and hydrochloric acid (HCl) produces hydrogen gas (H2). If 0.25 moles of zinc are completely reacted, calculate the volume of H2 gas produced at STP.
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First, we need to determine the balanced chemical equation for the reaction between zinc and hydrochloric acid:
Zn + 2HCl → ZnCl2 + H2
From the equation, we can see that every 1 mole of zinc produces 1 mole of hydrogen gas.
Given that 0.25 moles of zinc are completely reacted, we can conclude that 0.25 moles of hydrogen gas will be produced.
Now, we can use the ideal gas law to calculate the volume of hydrogen gas at STP (Standard Temperature and Pressure):
PV = nRT
P = pressure = 1 atm (at STP)
V = volume (unknown)
n = number of moles of gas = 0.25 moles
R = ideal gas constant = 0.0821 L·atm/(mol·K)
T = temperature = standard temperature = 273.15 K
Rearranging the equation to solve for V:
V = nRT/P
V = (0.25 moles)(0.0821 L·atm/(mol·K))(273.15 K)/(1 atm)
V ≈ 5.59 L
Therefore, approximately 5.59 liters of hydrogen gas will be produced at STP.
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