A mother is three and a half times as old as her daughter now. Five years ago, the sum of their ages was equal to the mother’s age four years from now. Taking the daughter’s present age as d years, find the mother’s actual age in 15 years.
Guide On Rating System
Vote
Let's start by solving the equations based on the information given.
Let the daughter's present age be d.
According to the first statement, the mother is three and a half times as old as the daughter. This can be written as: 3.5d = mother's age.
Five years ago, the daughter was d - 5 years old and the mother was 3.5d - 5 years old.
According to the second statement, the sum of their ages five years ago was equal to the mother's age four years from now. This can be written as: (d - 5) + (3.5d - 5) = 3.5d + 4.
Simplifying this equation, we get: 4.5d - 10 = 3.5d + 4.
Bringing the terms involving d to one side, we get: 1d = 18.
Therefore, the daughter's present age d = 18.
To find the mother's actual age in 15 years, we add 15 years to her current age: 3.5(18) + 15 = 87 years.
Therefore, the mother's actual age in 15 years is 87 years.
Got a question with my answer?
Cheapmath.com is completely free!
Asking question is free.
Getting answers is free.
+99