Question
A mixture was found to contain 3.10 g of SiO2, 0.38 g of cellulose, and 6.72g of calcium carbonate. What is the percentage of CaCO3 in this mixture?
A mixture was found to contain 3.10 g of SiO2, 0.38 g of cellulose, and 6.72g of calcium
carbonate. What is the percentage of CaCO3 in this mixture?
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Koala Tutor
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To find the percentage of CaCO3 in the mixture, we need to use the formula:
(grams of CaCO3 / total grams of the mixture) × 100
First, let's calculate the total weight of the mixture:
Total weight = grams of SiO2 + grams of cellulose + grams of CaCO3
Total weight = 3.10 g + 0.38 g + 6.72 g
Total weight = 10.20 g
Now, let's calculate the percentage of CaCO3 in the mixture:
Percentage of CaCO3 = (6.72 g / 10.20 g) × 100
Percentage of CaCO3 ≈ 65.88%
Therefore, the percentage of CaCO3 in this mixture is approximately 65.88%.
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