A laboratory analysis of a metal ore sample shows that it contains 20% iron (Fe) by mass. Calculate the mass of the ore sample required to obtain 2 moles of pure iron.
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To calculate the mass of the ore sample required to obtain 2 moles of pure iron, we first need to determine the molar mass of iron (Fe).
The molar mass of Fe is 55.85 grams/mole.
To obtain 2 moles of pure iron, we would need 2 moles * 55.85 grams/mole = 111.7 grams of iron.
Since the ore sample contains 20% iron by mass, this means that 100% - 20% = 80% of the mass of the ore sample is composed of other materials.
Therefore, we can set up the following equation:
0.8 x mass of the ore sample = 111.7 grams
Dividing both sides of the equation by 0.8, we find that the mass of the ore sample required to obtain 2 moles of pure iron is:
mass of the ore sample = 111.7 grams / 0.8 = 139.625 grams
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