A group of students is organizing a bake sale to raise money for their school trip. They plan to sell two types of cookies, chocolate chip cookies, and oatmeal cookies. The number of chocolate chip cookies they plan to bake is represented by the variable 'c', and the number of oatmeal cookies is represented by the variable 'o'.
The total cost to bake 'c' chocolate chip cookies is given by the expression 0.75c, and the total cost to bake 'o' oatmeal cookies is given by the expression 0.50o.
If the students plan to bake a total of 100 cookies, write an algebraic expression to represent the total cost of baking all the cookies. Also, determine the total cost if they bake 30 chocolate chip cookies and 70 oatmeal cookies.
Hint: To find the total cost, you need to add the cost of baking chocolate chip cookies to the cost of baking oatmeal cookies. If you need a perfect math homework help solution then you can also visit helpinhomework.org
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To find the total cost of baking all the cookies, we need to add the cost of baking the chocolate chip cookies to the cost of baking the oatmeal cookies.
The cost to bake 'c' chocolate chip cookies is given by 0.75c.
The cost to bake 'o' oatmeal cookies is given by 0.50o.
Since the total number of cookies is 100, we know that c + o = 100.
To represent the total cost of baking all the cookies, we add the two expressions for the cost of baking the different types of cookies:
Total cost = 0.75c + 0.50o
Now, let's determine the total cost if they bake 30 chocolate chip cookies and 70 oatmeal cookies.
Plugging in c = 30 and o = 70 into the expression for the total cost, we get:
Total cost = 0.75(30) + 0.50(70)
Total cost = 22.50 + 35
Total cost = 57.50
Therefore, the total cost of baking 30 chocolate chip cookies and 70 oatmeal cookies would be $57.50.
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