A diver jumps off a diving board into a swimming pool. Determine the diver's velocity when they hit the water, given that the height of the diving board is 10 meters.
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To determine the diver's velocity when they hit the water, we can use the equation of motion:
v^2 = u^2 + 2as
Here, v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (approximately 9.8 m/s^2), and s is the displacement.
Since the diver starts from rest on the diving board, the initial velocity (u) is 0 m/s. The displacement (s) is the height of the diving board, which is 10 meters.
Plugging in these values, the equation becomes:
v^2 = 0^2 + 2(9.8)(10)
Simplifying,
v^2 = 196
Taking the square root of both sides,
v = √196
v ≈ 14 m/s
Therefore, the diver's velocity when they hit the water is approximately 14 m/s.
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