Question
Jan Villaroel
Topic: Physics Posted 1 year ago
A charged particle with a velocity of 10 m/s enters a magnetic field at right angles to the field lines. If the magnetic field strength is 0.5 T, calculate the radius of the particle's circular path.

A charged particle with a velocity of 10 m/s enters a magnetic field at right angles to the field lines. If the magnetic field strength is 0.5 T, calculate the radius of the particle's circular path.


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Koala Tutor
Oct 3, 2023
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The formula to calculate the radius of the particle's circular path in a magnetic field is given by:

r = (m*v)/(q*B)

Where:
r = radius of the circular path
m = mass of the charged particle
v = velocity of the charged particle
q = charge of the particle
B = magnetic field strength

Given:
v = 10 m/s
B = 0.5 T

To find the radius, we first need to know the mass and charge of the particle. Let's assume the particle is an electron, which has a charge of -e and a mass of 9.10938356 × 10^-31 kg (according to the International System of Units).

Plugging in the values:

r = (m*v)/(q*B)
r = (9.10938356 × 10^-31 kg * 10 m/s)/(-1.602176634 × 10^-19 C * 0.5 T)

Calculating the expression:

r = (9.10938356 × 10^-30 kg * m)/(3.204025038 × 10^-19 C * T)
r = 2.846079189 × 10^-11 m

Therefore, the radius of the particle's circular path is approximately 2.85 × 10^-11 m.

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