Question
A cash register contains $10 bills and $50 bills with a total value of $1080. If there are 28 bills total, then how many of each does the register contain?
A cash register contains $10 bills and $50 bills with a total value of $1080. If there are 28 bills total, then how many of each does the register contain?
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Koala Tutor
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Let the number of $10 bills be $x$, then the number of $50 bills is $28-x$.
The total value of the $10 bills is then $10x$.
The total value of the $50 bills is then $50(28-x)$.
The total value of the register is $10x + 50(28-x) = 1080$.
Simplifying the equation gives $10x + 1400 - 50x = 1080$.
Combining like terms gives $-40x + 1400 = 1080$.
Subtracting 1400 from both sides gives $-40x = -320$.
Dividing both sides by -40 gives $x = 8$.
So there are 8 $10 bills and 28-8=<<8=20>>20 $50 bills. Answer: \boxed{8, 20}.
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