Question
A baseball diamond is a square that is 90 feet on each side. What is the distance a catcher has to throw the ball from home to second base?
A baseball diamond is a square that is 90 feet on each side. What is the distance a catcher has to throw the ball from home to second base?
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The distance from home to second base on a baseball diamond can be found using the Pythagorean theorem, since it forms a right triangle with the 90-foot sides being the two legs.
By applying the Pythagorean theorem, the distance (d) from home to second base can be calculated as:
d² = 90² + 90²
d² = 8100 + 8100
d² = 16200
Taking the square root of both sides:
d = √16200 ≈ 127.28
Therefore, the distance a catcher has to throw the ball from home to second base is approximately 127.28 feet.
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