A $5,000 principal is invested in two accounts, one earning 1% interest and another earning 6% interest. If the total interest for the year is $170, then how much is invested in each account?
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Let x be the amount invested in the account earning 1% interest.
The amount invested in the account earning 6% interest is 5000 - x.
The total interest earned by the amount invested in the account earning 1% interest is x * 0.01.
The total interest earned by the amount invested in the account earning 6% interest is (5000 - x) * 0.06.
The total interest for both accounts is x * 0.01 + (5000 - x) * 0.06 = $170.
Multiplying through the parentheses, we get (0.06) * 5000 - (0.06)*x + (0.01)*x = 170.
Multiplying through the parentheses again, we get 300 - 0.06*x + 0.01*x = 170.
Combining like terms, we get 0.05*x = 130.
Dividing both sides by 0.05, we get x = 2600. Answer: \boxed{2600}.
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