Question
Jan Villaroel
Topic: Chemistry Posted 1 year ago
A 0.10 M silver nitrate (AgNO3) solution is mixed with a 0.20 M sodium chloride (NaCl) solution. Calculate the mass of silver chloride (AgCl) that will precipitate out.

A 0.10 M silver nitrate (AgNO3) solution is mixed with a 0.20 M sodium chloride (NaCl) solution. Calculate the mass of silver chloride (AgCl) that will precipitate out.


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Koala Tutor
Oct 9, 2023
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To determine the mass of silver chloride (AgCl) that will precipitate out, we first need to determine the balanced chemical equation representing the reaction.

The balanced chemical equation for the reaction between silver nitrate (AgNO3) and sodium chloride (NaCl) is:

AgNO3 + NaCl → AgCl + NaNO3

From the balanced equation, we can see that 1 mole of AgNO3 reacts with 1 mole of NaCl to produce 1 mole of AgCl.

To calculate the mass of AgCl produced, we need to determine the limiting reactant. The limiting reactant is the reactant that is completely consumed, thereby determining the maximum amount of product that can be formed.

To determine the limiting reactant, we need to compare the number of moles of each reactant.

1. Determine the moles of AgNO3:

Moles of AgNO3 = concentration (M) x volume (L)
Moles of AgNO3 = 0.10 M x volume (L)

2. Determine the moles of NaCl:

Moles of NaCl = concentration (M) x volume (L)
Moles of NaCl = 0.20 M x volume (L)

The limiting reactant will be the one that produces fewer moles of AgCl.

3. Compare the moles of AgNO3 and NaCl to determine the limiting reactant:

If the moles of AgNO3 are less than the moles of NaCl, then AgNO3 is the limiting reactant.
If the moles of AgNO3 are greater than the moles of NaCl, then NaCl is the limiting reactant.

4. Once we have determined the limiting reactant, we can calculate the number of moles of AgCl produced.

If AgNO3 is the limiting reactant, then the number of moles of AgCl produced is equal to the moles of AgNO3.

If NaCl is the limiting reactant, then the number of moles of AgCl produced is equal to the moles of NaCl.

5. Finally, we can calculate the mass of AgCl produced using the molar mass of AgCl.

Mass of AgCl = moles of AgCl x molar mass of AgCl

Remember to convert the volume (L) to moles in steps 1 and 2 if necessary.

Please provide the volume (L) of each solution in order to continue the calculation.

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