A 0.025 M solution of sodium hydroxide (NaOH) is used to titrate 50.0 mL of hydrochloric acid (HCl). If it takes 28.2 mL of the sodium hydroxide solution to neutralize the acid, calculate the molarity of the hydrochloric acid solution.
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To find the molarity of the hydrochloric acid solution, we can set up a balanced chemical equation for the reaction:
HCl + NaOH -> NaCl + H2O
From the equation, we can see that 1 mole of HCl reacts with 1 mole of NaOH. Therefore, the moles of NaOH used in the reaction would be the same as the moles of HCl in the hydrochloric acid solution.
The moles of NaOH used can be calculated using the molarity and volume of NaOH solution:
0.025 M NaOH * 0.0282 L NaOH = 7.05 x 10^-4 moles NaOH
Since the moles of NaOH used is equal to the moles of HCl in the reaction, the molarity of the hydrochloric acid solution can be calculated using the volume of HCl solution:
Molarity of HCl = Moles of HCl / Volume of HCl
Molarity of HCl = 7.05 x 10^-4 moles HCl / 0.0500 L HCl
Molarity of HCl = 0.0141 M
Therefore, the molarity of the hydrochloric acid solution is 0.0141 M.
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